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NEW QUESTION: 1
Users require access to a certain server depending on their job function. Which of the following would be the MOST appropriate strategy for securing the server?
A. Mandatory access control
B. Role based access control
C. Discretionary access control
D. Common access card
Answer: B
Explanation:
Role-based Access Control is basically based on a user's job description. When a user is assigned a specific role in an environment, that user's access to objects is granted based on the required tasks of that role.
Incorrect Answers:
A. Smart cards are credit-card-sized IDs, badges, or security passes with an embedded integrated circuit chip.
Common Access Cards (CACs) are the U.S. government and military version of a smart card.
C. Discretionary access control (DAC) allows access to be granted or restricted by an object's owner based on user identity and on the discretion of the object owner. It does not rely on job function.
D. Mandatory Access Control allows access to be granted or restricted based on the rules of classification. It does not rely on job function.
References:
Stewart, James Michael, CompTIA Security+ Review Guide, Sybex, Indianapolis, 2014, pp. 278-284
NEW QUESTION: 2
Which two default endpoint identity groups does Cisco ISE create? (Choose two )
A. block list
B. endpoint
C. unknown
D. profiled
E. allow list
Answer: C,D
Explanation:
Explanation
https://www.cisco.com/c/en/us/td/docs/security/ise/2-1/admin_guide/b_ise_admin_guide_21/b_ise_admin_guide Default Endpoint Identity Groups Created for EndpointsCisco ISE creates the following five endpoint identity groups by default: Blacklist, GuestEndpoints, Profiled, RegisteredDevices, and Unknown. In addition, it creates two more identity groups, such as Cisco-IP-Phone and Workstation, which are associated to the Profiled (parent) identity group. A parent group is the default identity group that exists in the system.
Cisco ISE creates the following endpoint identity groups:
* Blacklist-This endpoint identity group includes endpoints that are statically assigned to this group in Cisco ISE and endpoints that are block listed in the device registration portal. An authorization profile can be defined in Cisco ISE to permit, or deny network access to endpoints in this group.
* GuestEndpoints-This endpoint identity group includes endpoints that are used by guest users.
* Profiled-This endpoint identity group includes endpoints that match endpoint profiling policies except Cisco IP phones and workstations in Cisco ISE.
* RegisteredDevices-This endpoint identity group includes endpoints, which are registered devices that are added by an employee through the devices registration portal. The profiling service continues to profile these devices normally when they are assigned to this group. Endpoints are statically assigned to this group in Cisco ISE, and the profiling service cannot reassign them to any other identity group.
These devices will appear like any other endpoint in the endpoints list. You can edit, delete, and block these devices that you added through the device registration portal from the endpoints list in the Endpoints page in Cisco ISE. Devices that you have blocked in the device registration portal are
* assigned to the Blacklist endpoint identity group, and an authorization profile that exists in Cisco ISE redirects blocked devices to a URL, which displays "Unauthorised Network Access", a default portal page to the blocked devices.
* Unknown-This endpoint identity group includes endpoints that do not match any profile in Cisco ISE.
In addition to the above system created endpoint identity groups, Cisco ISE creates the following endpoint identity groups, which are associated to the Profiled identity group:
* Cisco-IP-Phone-An identity group that contains all the profiled Cisco IP phones on your network.
* Workstation-An identity group that contains all the profiled workstations on your network.
NEW QUESTION: 3
コードの断片を考えると：
行7に挿入されると、100の印刷を可能にするコードフラグメントはどれですか？
A. ToIntFunction<Integer> funRef = e ?gt; e + 10;
int result = funRef.applyAsInt (value);
B. ToIntFunction funRef = e ?gt; e + 10;
int result = funRef.apply (value);
C. Function<Integer> funRef = e ?gt; e + 10;
Integer result = funRef.apply(value);
D. IntFunction funRef = e ?gt; e + 10;
Integer result = funRef.apply (10);
Answer: C