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NEW QUESTION: 1
Your network contains an Active Directory domain named contoso.com. The domain contains two member
servers named Server1 and Server2.
All servers run Windows Server 2012. Server1 and Server2 are nodes in a Hyper-V cluster named Cluster1.
Cluster1 hosts 10 virtual machines.
All of the virtual machines run Windows Server 2012 and are members of the domain.
You need to ensure that the first time a service named Service1 fails on a virtual machine, the virtual
machine is moved to a different node.
You configure Service1 to be monitored from Failover Cluster Manager.
What should you configure on the virtual machine?
A. From the Recovery settings of Service1, set the First failure recovery action to Restart the Service.
B. From the Recovery settings of Service1, set the First failure recovery action to Take No Action.
C. From the General settings, modify the Service status.
D. From the General settings, modify the Startup type.
Answer: B
Explanation:
Virtual machine application monitoring and management In clusters running Windows Server 2012, administrators can monitor services on clustered virtual machines that are also running Windows Server 2012. This functionality extends the high-level monitoring of virtual machines that is implemented in Windows Server 2008 R2 failover clusters. If a monitored service in a virtual machine fails, the service can be restarted, or the clustered virtual machine can be restarted or
moved to another node (depending on service restart settings and cluster failover settings). This feature increases the uptime of high availability services that are running on virtual machines within a failover cluster.
Windows Server 2012 Failover Cluster introduces a new capability for Hyper-V virtual machines (VMs), which is a basic monitoring of a service within the VM which causes the VM to be rebooted should the monitored service fail three times. For this feature to work the following must be configured:
-Both the Hyper-V servers must be Windows Server 2012 and the guest OS running in theVM must be Windows Server 2012.
-The host and guest OSs are in the same or at least trusting domains.
-The Failover Cluster administrator must be a member of the local administrator's group inside the VM.
-Ensure the service being monitored is set to Take No Action (see screen shot below) within the guest VM for Subsequent failures (which is used after the first and second failures) and is set via the Recovery tab of the service properties within the Services application (services.msc).
-Within the guest VM, ensure the Virtual Machine Monitoring firewall exception is enabled for the Domain network by using the Windows Firewall with Advanced Security application or by using the Windows PowerShell command below: Set-NetFirewallRule -DisplayGroup "Virtual Machine Monitoring" -Enabled True
After the above is true, enabling the monitoring is a simple process:
1.Launch the Failover Cluster Manager tool.
2.Navigate to the cluster - Roles.
3.Right click on the virtual machine role you wish to enable monitoring for and under More Actions select Configure Monitoring...
4.The services running inside the VM will be gathered and check the box for the services that should be monitored and click OK.
You are done!
Monitoring can also be enabled using the Add-ClusterVMMonitoredItem cmdlet and -VirtualMachine, with the -Service parameters, as the example below shows: PS C:\Windows\system32> Add-ClusterVMMonitoredItem -VirtualMachine savdaltst01 -Service spooler
http://sportstoday.us/technology/windows-server-2012---continuous-availability-%28part-4%29---failoverclustering-enhancements---virtual-machine-monitoring-.aspx http://windowsitpro.com/windows-server-2012/enable-windows-server-2012-failover-cluster-hyper-v-vmmonitoring
NEW QUESTION: 2
You have multiple workbook queries that load data from tables in Microsoft Azure SQL Database to a Power Pivot data model.
You discover that new rows were added to the tables in Azure SQL Database.
You need to ensure that the workbook has the new data.
Why should you do?
A. Close and open the workbook.
B. Select a cell in the worksheet and pressF5.
C. From the Power Pivot tab, click Update All.
D. From the data tab, click Refresh All.
Answer: D
Explanation:
Explanation
Refresh data from a Microsoft Query, the Data Connection Wizard, or web query
* Click any cell in the range or table that contains the link to the external data.
* On the Data tab, in the Connections group, click Refresh All.
* To update only the selected data, click
You can also right-click a cell in the range or table, and then click
* To update all the data connections in the workbook, click
Note: If you have more than one workbook open, you'll need to repeat the operation in each workbook.
https://support.office.com/en-us/article/refresh-an-external-data-connection-in-excel-2016-for-windows-1524175
NEW QUESTION: 3
You plan to deploy an application by using three Azure virtual machines (VMs). The application has a web-based component that uses TCP port 443 and a custom component that uses UDP port 2020.
The application must be available during planned and unplanned Azure maintenance events. Incoming client requests must be distributed across the three VMs. Clients must be connected to a VM only if both application components are running.
You need to configure the VM environment.
For each requirement, what should you implement? To answer, drag the appropriate configuration type to the correct target. Each configuration type may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
Explanation
Box 1:
availability set.
Box 2:
backend pool.
Box 3:
health probe.
References:
https://docs.microsoft.com/en-us/azure/guidance/guidance-compute-multi-vm
NEW QUESTION: 4
The Data Encryption Standard (DES) encryption algorithm has which of the following characteristics?
A. 64 bit blocks with a 64 bit total key length
B. 64 bits of data input results in 56 bits of encrypted output
C. 56 bits of data input results in 56 bits of encrypted output
D. 128 bit key with 8 bits used for parity
Answer: A
Explanation:
Explanation/Reference:
DES works with 64 bit blocks of text using a 64 bit key (with 8 bits used for parity, so the effective key length is 56 bits).
Some people are getting the Key Size and the Block Size mixed up. The block size is usually a specific length. For example DES uses block size of 64 bits which results in 64 bits of encrypted data for each block. AES uses a block size of 128 bits, the block size on AES can only be 128 as per the published standard FIPS-197.
A DES key consists of 64 binary digits ("0"s or "1"s) of which 56 bits are randomly generated and used directly by the algorithm. The other 8 bits, which are not used by the algorithm, may be used for error detection. The 8 error detecting bits are set to make the parity of each 8-bit byte of the key odd, i.e., there is an odd number of "1"s in each 8-bit byte1. Authorized users of encrypted computer data must have the key that was used to encipher the data in order to decrypt it.
IN CONTRAST WITH AES
The input and output for the AES algorithm each consist of sequences of 128 bits (digits with values of 0 or
1). These sequences will sometimes be referred to as blocks and the number of bits they contain will be referred to as their length. The Cipher Key for the AES algorithm is a sequence of 128, 192 or 256 bits.
Other input, output and Cipher Key lengths are not permitted by this standard.
The Advanced Encryption Standard (AES) specifies the Rijndael algorithm, a symmetric block cipher that can process data blocks of 128 bits, using cipher keys with lengths of 128, 192, and 256 bits. Rijndael was designed to handle additional block sizes and key lengths, however they are not adopted in the AES standard.
The AES algorithm may be used with the three different key lengths indicated above, and therefore these different "flavors" may be referred to as "AES-128", "AES-192", and "AES-256".
The other answers are not correct because:
"64 bits of data input results in 56 bits of encrypted output" is incorrect because while DES does work with
64 bit block input, it results in 64 bit blocks of encrypted output.
"128 bit key with 8 bits used for parity" is incorrect because DES does not ever use a 128 bit key.
"56 bits of data input results in 56 bits of encrypted output" is incorrect because DES always works with 64 bit blocks of input/output, not 56 bits.
Reference(s) used for this question:
Official ISC2 Guide to the CISSP CBK, Second Edition, page: 336-343
http://csrc.nist.gov/publications/fips/fips197/fips-197.pdf
http://csrc.nist.gov/publications/fips/fips46-3/fips46-3.pdf