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NEW QUESTION: 1
회사가 AWS에서 새로운 고 가용성 웹 애플리케이션을 설계하고 있습니다. 애플리케이션은 AWS의 애플리케이션 서버에서 회사의 온 프레미스 환경에서 호스팅되는 백엔드 REST API로 일관되고 안정적인 연결이 필요합니다. AWS와 온 프레미스 간의 백엔드 연결은 프라이빗 가상 인터페이스를 통해 AWS Direct Connect 연결을 통해 라우팅됩니다. Amazon Route 53은 애플리케이션이 백엔드 REST API의 IP 주소를 확인하기 위한 프라이빗 DNS 레코드를 관리하는 데 사용됩니다.
어떤 디자인이 백엔드 API에 안정적인 연결을 제공합니까?
A. 동일한 네트워크 캐리어에서 동일한 Direct Connect 연결을위한 두 번째 교차 연결을 설치하고 동일한 개인 가상 인터페이스에서 동일한 LAG (Link Aggregation Group)에 두 연결을 결합하십시오.
B. 다른 네트워크 캐리어에서 두 번째 Direct Connect 연결을 설치하고 첫 번째 Direct Connect 연결과 동일한 가상 사설 게이트웨이에 연결하십시오.
C. 백엔드 REST API에 대해 두 개 이상의 백엔드 엔드 포인트를 구현하고 Route 53 상태 점검을 사용하여 각 백엔드 엔드 포인트의 가용성을 모니터하고 DNS 레벨 장애 복구를 수행하십시오.
D. 온 프레미스 데이터 센터에서 AWS로 퍼블릭 인터넷을 통해 라우팅 된 IPSec VPN 연결을 생성하고 Direct Connect 연결과 동일한 가상 프라이빗 게이트웨이에 연결합니다.
Answer: C
Explanation:
Explanation
https://aws.amazon.com/answers/networking/aws-single-data-center-ha-network-connectivity/
NEW QUESTION: 2
Given the code fragment:
List<String> nL = Arrays.asList("Jim", "John", "Jeff");
Function<String, String> funVal = s -> "Hello : ".concat(s);
nL.Stream()
.map(funVal)
.forEach(s-> System.out.print (s));
What is the result?
A. The program prints nothing.
B. Hello : Jim Hello : John Hello : Jeff
C. A compilation error occurs.
D. Jim John Jeff
Answer: A
Explanation:
Explanation
The program prints nothing because the method is concat.
NEW QUESTION: 3
Your company has an IPv4 Ethernet network.
A router named R1 connects your segment to the Internet. A router named R2 joins your subnet with a segment named Private1. The Private1 segment has a network address of 10.128.4.0/26. Your computer named WKS1 requires access to servers on the Private1 network. The WKS1 computer configuration is as shown in the following table.
WKS1 is unable to connect to the Private1 network by using the current configuration. You need to add a persistent route for the Private1 network to the routing table on WKS1.
Which command should you run on WKS1?
A. Route add -p 10.128.4.0 mask 255.255.255.192 10.128.64.1
B. Route add -p 10.128.64.10 mask 255.255.255.192 10.128.4.0
C. Route add -p 10.128.4.0/22 10.128.4.1
D. Route add -p 10.128.4.0/26 10.128.64.10
Answer: D