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NEW QUESTION: 1
Sie stellen einen Azure Kubernetes Service (AKS) -Cluster mit dem Namen Cluster1 bereit, der die in der folgenden Tabelle angegebenen IP-Adressen verwendet.

Sie müssen Internetbenutzern Zugriff auf die Anwendungen gewähren, die in Cluster1 ausgeführt werden.
Welche IP-Adresse sollten Sie in den DNS-Eintrag für Ousted aufnehmen?
A. 192.168.10.2
B. 131.107.2.1
C. 10.0.10.11
D. 172.17.7.1
Answer: B
Explanation:
When any internet user will try to access the cluster which is behind a load balancer, traffic will first hit to load balancer front end IP. So in the DNS configuration you have to provide the IP address of the load balancer.
Reference:
https://stackoverflow.com/questions/43660490/giving-a-dns-name-to-azure-load-balancer

NEW QUESTION: 2
Domain Name Service is a distributed database system that is used to map:
A. Domain Name to IP addresses.
B. IP addresses to MAC Addresses.
C. MAC addresses to domain names.
D. MAC Address to IP addresses.
Answer: A
Explanation:
The Domain Name Service is a distributed database system that is used to map domain names to IP addresses and IP addresses to domain names.
The Domain Name System is maintained by a distributed database system, which uses the client-server model. The nodes of this database are the name servers. Each domain has at least one authoritative DNS server that publishes information about that domain and the name servers of any domains subordinate to it. The top of the hierarchy is served by the root nameservers, the servers to query when looking up (resolving) a TLD.
Reference(s) used for this question:
KRUTZ, Ronald L. & VINES, Russel D., The CISSP Prep Guide: Mastering the Ten
Domains of Computer Security, 2001, John Wiley & Sons, Page 100.
and
https://en.wikipedia.org/wiki/Domain_Name_System

NEW QUESTION: 3
The network administrator is asked to configure 113 point-to-point links. Which IP addressing scheme defines the address range and subnet mask that meet the requirement and waste the fewest subnet and host addresses?
A. 10.10.0.0/18 subnetted with mask 255.255.255.252
B. 10.10.1.0/25 subnetted with mask 255.255.255.252
C. 10.10.0.0/16 subnetted with mask 255.255.255.252
D. 10.10.1.0/24 subnetted with mask 255.255.255.252
E. 10.10.0.0/23 subnetted with mask 255.255.255.252
Answer: E
Explanation:
We need 113 point-to-point links which equal to 113 sub-networks < 128 so we need to borrow 7 bits (because 2

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7 = 128).
The network used for point-to-point connection should be /30.
So our initial network should be 30 - 7 = 23.
So 10.10.0.0/23 is the correct answer.
You can understand it more clearly when writing it in binary form:
/23 = 1111 1111.1111 1110.0000 0000
/30 = 1111 1111.1111 1111.1111 1100 (borrow 7 bits)