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NEW QUESTION: 1
During a workshop, a customer asks you to explain the functionality and major benefits of HP StoreOnce Catalyst. What are benefits of HP StoreOnce Catalyst? (Select two.)
A. moves data between sites and is seamlessly controlled by your HP StoreOnce system
B. allows seamless movement of deduplicated data across the enterprise to other HP StoreOnce Catalyst systems without rehydration
C. is available on the HP StoreOnce 44xx series, the HP StoreOnce VS and on the B6200
D. delivers a single, integrated, enterprise-wide deduplication algorithm and was developed by HP Labs
E. requires each Catalyst-enabled product to have a capacity-based HP StoreOnce Catalyst license
Answer: B,D
Explanation:
Reference:http://h20195.www2.hp.com/v2/GetPDF.aspx%2F4AA4-4500ENW.pdf(page 4, first para)
NEW QUESTION: 2
2 년 12 월 31 일에 기업은 다음과 같은 의무를 다시 재정비해야 했다.
17 % 노트는 1 년 10 월 1 일에 발행되었으며 3 월 7 일에 성숙합니다.
대차 대조표 일에 존재하는 대출 계약은 재 융자를 제공하지 않습니다. 15 % 지폐는 1 년 5 월 1 일에 발행되었고 3 년 5 월 1 일에 만기되었습니다. 3 년 2 월 1 일에, 17 % 지폐의 미화 140,000 달러 잔액은 장기 발행으로 재 융자되었습니다 부채 도구. 2 년 7 월 3 일, 기업은 장기적으로 지불 할 15 %의 메모를 재 융자하기 위해 대출자와 취소할 수 없는 계약을 체결했습니다. 재무 제표는 3 년 3 월 1 일에 발행 될 수 있도록 승인되었다. 회사의 12 월 31 일, 2 년차 대차 대조표에 따라 유동 부채에서 적절하게 배제 될 수 있는 총 부채는 다음과 같다.
A. US $ 340,000
B. US $ 200,000
C. US $ 0
D. US $ 140,000
Answer: C
Explanation:
Financial liabilities are current if they are due within 12 months even if1) the original term was for more than 12 months and2) an agreement to refinance on a long-term basis was completed after the balance sheet and before the issuance of the financial statements. Thus, both are current. The amount excluded from current liabilities is US $0.
NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:
You need to determine the total number of customers who have either deposit accounts or loan accounts, but not both types of accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
D. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
E. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
G. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
Answer: F
Explanation:
Explanation
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx