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NEW QUESTION: 1
CORRECT TEXT

Topology Details:
AS64520

AS64525

Simulation requirements:



Answer:
Explanation:
Check the complete solution below:
Explanation:
for EBGP and IBGP lab you have to make correction to the configuration in a router R1.
You have only access to Router R1.
R1 and RA should be neighbors through EBGP.
in R1 you will find this command:
(config-router)#Neighbor 209.165.277.2 remote-as 64525
The ip address here is wrong , delete this command using :
(config-router)#No Neighbor 209.165.277.2 remote-as 64525
And replace it with new command with right ip of RA E0/1 interface
by typing this command:
(config-router)#Neighbor 209.165.201.2 remote-as 64525
R1 and R2 and R3 are neighbors through IBGP, and R1 use the peer-group IBGP to form neighborship between R1 and R2, and between R1 and R3, but actually there issue with the IBGP peer-group commands in R1 You will find in R1 these following commands:
(config-router)#neighbor IBGP peer-group
(config-router)#neighbor IBGP remote-as 64550
(config-router)#neighbor IBGP next-hop-self
(config-router)#neighbor IBGP update-source loopback 0
You must correct the Remote-AS for the Peer-Group IBGP to 64520 to form the neighborship correctly.
Watch Out! If you delete the config with " no neighbor IBGP remote-as 64550" you also will delete the following lines:
(config-router)#neighbor IBGP peer-group
(config-router)#neighbor IBGP next-hop-self
(config-router)#neighbor IBGP update-source loopback 0
So don't delete the line regarding the " remote-as".
Just replace it with:
(config-router)#neighbor IBGP remote-as 64520
In the Scenario regarding the Lab, they tell you how the routing-table should look if you have done everything right!
So if you routing-table on R1 looks like the one they posted in the scenario you have done everything right and can go on to the next topic.
You have to use the command "#show ip bgp " to show bgp routing table , don't use "#show ip route" command

NEW QUESTION: 2
What happens after executing the following code?
DCL OUTFILE FILE RECORD OUTPUT;
DCLP PTR;
DCL I BIN FIXED(31);
DCL A BIN FIXED(31) BASED(P);
DO I = 1 TO 10;
LOCATE A FILE(OUTFILE) SET(P);
A = I;
END;
CLOSE FILE(OUTFILE);
A. 9 records will be written with value 1 to 9.
B. 10 records will be written with first record value undefined.
C. 9 records will be written with value 2 to 10.
D. 10 records will be written with value 1 to 10.
Answer: D

NEW QUESTION: 3
ユーザーがSSHを使用して実行中のEC2インスタンスに接続しようとしています。ただし、ユーザーはUnprotected Private Key Fileエラーを受け取ります。拒否の理由として考えられるのは、次のオプションのうちどれですか?
A. ユーザーがOSログインに間違ったユーザー名を指定しました
B. 秘密鍵ファイルのファイル許可が間違っています
C. SSHに使用されるppkファイルは読み取り専用です
D. 公開鍵ファイルに間違った許可があります
Answer: B
Explanation:
説明
EC2インスタンスに対してSSHを実行しているときに、保護されていない秘密キーファイルエラーが表示された場合、コンピューター上の秘密キーファイルの権限が開いていることを意味します。理想的には、秘密鍵には0400のUnix許可が必要です。これを修正するには、次のコマンドを実行します。
chmod 0400 /path/to/private.key