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NEW QUESTION: 1
View the Exhibit and examine the structure of the PROMOTIONS table.
Using the PROMOTIONS table, you need to find out the names and cost of all the promos done on 'TV' and 'internet' that ended in the time interval 15th March '00 to 15th October
'00.
Which two queries would give the required result? (Choose two.)
A. SELECT promo_name, promo_costFROM promotionsWHERE promo_category IN ('TV',
'internet') ANDpromo_end_date BETWEEN '15-MAR-00' AND '15-OCT-00';
B. SELECT promo_name, promo_costFROM promotionsWHERE promo_category = 'TV' OR promo_category ='internet' AND promo_end_date >='15-MAR-00' OR promo_end_date
< ='15-OCT-00';
C. SELECT promo_name, promo_costFROM promotionsWHERE (promo_category
BETWEEN 'TV' AND 'internet') AND(promo_end_date IN ('15-MAR-00', '15-OCT-00'));
D. SELECT promo_name, promo_costFROM promotionsWHERE (promo_category = 'TV' OR promo_category ='internet') AND (promo_end_date >='15-MAR-00' AND promo_end_date <='15-OCT-00');
Answer: A,D
NEW QUESTION: 2
どの三つ声明が、仕事チェーンについて真実ですか？
A. イベントベースまたは時間ベースのスケジュールを使用して実行できます。
B. チェーン内の複数のステップで同じプログラムまたはネストされたチェーンを呼び出すことはできません。
C. ネストされた一連のジョブを含めることができます。
D. 複数の依存関係を持つことはできません。
E. これは、依存関係に基づくスケジューリングの実装に使用できます。
Answer: A,C,E
NEW QUESTION: 3
If the square of a number is added to the number increased by 4, the result is 60. If n represents the number, which equation can be used to find n ?
A. Option C
B. Option D
C. Option E
D. Option B
E. Option A
Answer: A
Explanation:
Explanation/Reference:
Explanation:
2 2
Let n = number. Then n = square of a number, and n + n + 4 = 60.
NEW QUESTION: 4
シナリオ
トポロジを参照してください。
会社がルーターR1を接続しました。 R2。シリアルリンク付きのR3。
R2とR3は、それぞれスイッチSW1とSW2に接続されています。
SW1とSW2は、ルーターR4とR5にも接続されています。
EIGRPルーティングプロトコルが設定されます。
さまざまなルーター間のEIGRPの問題をトラブルシューティングして解決する必要があります。
適切なshowコマンドを使用して、問題をトラブルシューティングします。
トラフィックはR1からR5までどのパスをたどりますか？
A. トラフィックは、R2とR3で均等に負荷分散されます。
B. トラフィックはR2を通過します。
C. トラフィックはR3を通過します。
D. トラフィックはR2とR3で不均等に負荷分散されます。
Answer: B
Explanation:
Using the "show ip int brief command" on R5 we can see the IP addresses assigned to this router. Then, using the "show ip route" command on R1 we can see that to reach 10.5.5.5 and
10.5.5.55 the preferred path is via Serial 1/3, which we see from the diagram is the link to R2.