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NEW QUESTION: 1
計画担当者が注文に在庫品目を追加すると、注文に関連して次に実行されるアクティビティはどれですか。
この質問には3つの正解があります。
応答：
A. 資材提供リストを印刷します。
B. 利用可能在庫確認を実行します。
C. 発注書を作成します。
D. 入庫を転記します。
E. 出庫を転記します。
Answer: A,B,E
NEW QUESTION: 2
You are a NACE Level 2 in-house inspector working in a shop. Your in-house requires you to perform a sleeve test to test for soluble salts; however the 3 rd party NACE Level 3 inspector, the owner, has a san smart meter and has achieved a very different result and has rejected the pre-cleaning.
Your FIRST course of action is to:
A. Redo the pre-cleaning based on the other inspectors results
B. Advise the other inspector he is using an incorrect method
C. Review the specification with the other inspector to see what method was specified
D. Advise your QC Manager to change the ITP to the use of the salt smart meter
Answer: C
NEW QUESTION: 3
Between which two types of ports does FIP establish Fibre Channel virtual links? (Choose two.)
A. E Ports and E Ports
B. N Ports and F Ports
C. VP Ports and VE Ports
D. VE Ports and VF Ports
E. VN Ports and VF Ports
F. VE Ports and VE Ports
Answer: E,F
Explanation:
FIP aims to establish virtual FC links between VN_Ports and VF_Ports (ENode to FCF), as well as between pairs of VE_Ports (FCF to FCF), since these are the only legal combinations supported by native Fibre Channel fabrics. Standards-compliant implementations are not required to support both forms of virtual FC links, and Cisco has decided to focus initially on implementing FIP only between ENodes and FCFs. FCF-to-
FCF connectivity is considered a strategic direction for end-to-end FCoE deployments, but the short-term urgency is for FCoE adoption between CNAs and the Fibre Channel fabric perimeter, where unified fabric can offer the greatest capital expenditure (CapEx) savings today.
Reference: http://www.cisco.com/c/en/us/products/collateral/switches/nexus-7000-series- switches/white_paper_c11-560403.html
NEW QUESTION: 4
A set of data from a process has 8 readings per sample and 50 samples. The mean of the 50 sample means is 12.62. The mean of the 50 ranges is 0.18.Find control limits for the R chart.
A. 0.10 and 0.25
B. none of the above
C. 0.02 and 0.33
D. none and 0.33
Answer: C
Explanation:
The formula required to calculate control limits for the R chart are as follows:
= 1.864 x 0.18 = 0.33
= 0.1111 x 0.18 = 0.02