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NEW QUESTION: 1
Add the Arrange Meeting tag to the contact ''Thomas Axen''. Set a start date of today and a due data of tomorrow. Set a reminder for 9:00 AM tomorrow.
Answer:
Explanation:
See below for solution.
Explanation
Go to contacts and search the ''Thomas Axen'' contact. Add follow up wit+h the following options
NEW QUESTION: 2
会社には、支払いが遅れることが多い長年の顧客がいます。同社は現在、このクライアントとの新しいプロジェクトを持っています。このプロジェクトの支払い遅延情報を確実に文書化するために、プロジェクトマネージャーはどの文書を使用する必要がありますか？
A. 履歴情報と学んだ教訓リポジトリ
B. プロジェクト憲章
C. 仮定ログ
D. リスク管理計画
Answer: C
NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:
Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, COUNT(OrderAmount) AS OrderAmount FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID ORDER BY OrderAmount DESC
B. SELECT CustomerID, CustomerName, ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY c.CustomerID ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName,
C. ShippingCountry) cs WHERE Rnk = 1
D. ShippingCountry, RANK() OVER (PARTITION BY c. CustomerID ORDER BY o. OrderAmount DESC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName,
E. ShippingCountry) cs WHERE Rnk = 1
F. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(OrderAmount) DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID Where o.Rnk = 1
G. SELECT CustomerID, CustomerName, ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName,
Answer: A