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NEW QUESTION: 1
A. Option C
B. Option D
C. Option E
D. Option F
E. Option A
F. Option B
Answer: B,E
NEW QUESTION: 2
Customers connecting to a Service Provider for Internet access are intending to implement redundant peering. The design requirements call for preferring a primary link for both ingress and egress traffic. Secondary links should be used only during primary outages. What two BGP deployment options will accomplish this design goal? (Choose two.)
A. On the router handling the primary link, advertise all routes with a longer AS-PATH value.
B. On the router handling the primary link, set the weight for all incoming routes to be a value of 0.
C. On the router handling the secondary link, advertise routes with a MED value of 0.
D. On the router handling the secondary link, set the local preference for all incoming routes to be a value of 0.
E. On the router handling the secondary link, advertise all routes with a longer AS-PATH value.
Answer: D,E
NEW QUESTION: 3
お客様がAWSへのAWS Direct Connect接続を確立しました。リンクはアップしており、ルートはお客様のエンドからアドバタイズされていますが、お客様はVPC内のEC2インスタンスからデータセンターにあるサーバーに接続できません。
この状況を改善するための実行可能なソリューションを提供するオプションは次のうちどれですか？ （2つ選択）
A. 'route'コマンドを使用して、すべてのインスタンスのルートテーブルを変更します。
B. iPsec VPN接続をターゲットとして、ルートテーブルにルートを追加します。
C. カスタマーゲートウェイ（CGW）へのルート伝播を有効にします。
D. 仮想Pinnateゲートウェイ（VGW）へのルート伝搬を有効にします。
E. 顧客のオンプレミス環境に戻るルートを追加して、Instances VPCサブネットルートテーブルを変更します。
Answer: D,E
NEW QUESTION: 4
あなたは次のコードを持っています。
すべての製品とその関連カテゴリを返す必要があります。
コードをどのように完成させるべきですか？ 答えを得るには、適切なコード要素を回答エリアの正しいターゲットにドラッグします。 各コード要素は、1回、複数回、またはまったく使用されなくてもよい。 コンテンツを表示するには、分割バーをペインの間にドラッグするかスクロールする必要があります。
Answer:
Explanation:
Explanation
Target 1: from
Target 2: join
Target 3: on
Target 4: equals
Example: Join operations create associations between sequences that are not explicitly modeled in the data sources. For example you can perform a join to find all the customers and distributors who have the same location. In LINQ the join clause always works against object collections instead of database tables directly.
C#
var innerJoinQuery =
from cust in customers
join dist in distributors on cust.City equals dist.City
select new { CustomerName = cust.Name, DistributorName = dist.Name };
Reference: https://msdn.microsoft.com/en-us/library/bb397927.aspx
https://msdn.microsoft.com/en-us/library/bb397927.aspx