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NEW QUESTION: 1
環境内のサーバーでマルウェアが疑われています。 アナリストは環境内のサーバーからのコマンドの出力を提供され、サーバーの1つで実行されているプロセスがマルウェアである可能性があるかどうかを判断するためにすべての出力ファイルを確認する必要があります。
説明書
サーバー1、2、4はクリック可能です。 マルウェアをホストするサーバーを選択し、このマルウェアをホストするプロセスを選択します。
シミュレーションの初期状態を元に戻したい場合は、リセットボタンを選択してください。
シミュレーションが完了したら、[完了]ボタンをクリックして送信してください。 シミュレーションが送信されたら、[次へ]ボタンをクリックして続行してください。
Answer:
Explanation:
Explanation
NEW QUESTION: 2
Which option for PROC COMPARE will list all observations and variables found in only one of the two data sets being compared?
A. LISTALL
B. OUTDIFF
C. ALLOBS
D. OUTALL
Answer: A
NEW QUESTION: 3
DRAG DROP
Answer:
Explanation:
NEW QUESTION: 4
Refer to the exhibit.
The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and 208.149.23.96?
A. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, Serial1/0
B. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, FastEthemet0/0
C. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via
190.173.23.10, 00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
D. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via
190.173.23.10, 00:00:16, FastEthemet0/0
Answer: D
Explanation:
Explanation/Reference:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -> The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost
108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0. In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.